2x+y^2/3x+3y

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Solution for 2x+y^2/3x+3y equation: 


x in (-oo:+oo)

2*x+x*((y^2)/3)+3*y = 0

1/3*x*y^2+3*y = 0 // - 3*y

1/3*x*y^2 = -(3*y) // : 1/3*y^2

x = (-(3*y))/(1/3*y^2)

x = -9*y^-1

x = -9*y^-1

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